An unbiased coin is tossed six times. Find the probability of obtaining more than 4 heads and less than 6 heads.

Solution

Here n = 6
p = Probability of head = $1 half comma space space straight q space equals space 1 space minus space straight p space equals space 1 minus 1 half space equals 1 half$
P(more than 4 heads and less than 6 heads) = P(5)
$equals space straight C presuperscript 6 subscript 5 space open parentheses 1 half close parentheses space open parentheses 1 half close parentheses to the power of 5 space equals space 6 space cross times space 1 half space cross times space 1 over 32 space equals 3 over 32 space equals space 0.0938$

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Probability

An unbiased coin is tossed six times. Find the probability of obtaining more than 4 heads and less than 6 heads.

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