An unbiased coin is tossed six times. Find the probability of obtaining more than 4 heads.

Solution

Here n = 6
p = Probability of head = $1 half comma space space straight q space equals space 1 space minus space straight p space equals space 1 minus 1 half space equals 1 half$
P (more than 4 heads) = P (5) + P (6)
$equals space straight C presuperscript 6 subscript 5 space open parentheses 1 half close parentheses space open parentheses 1 half close parentheses to the power of 5 space plus space straight C presuperscript 6 subscript 6 space open parentheses 1 half close parentheses to the power of 6 space equals space open parentheses 1 half close parentheses to the power of 6 space open square brackets straight C presuperscript 6 subscript 5 space plus space straight C presuperscript 6 subscript 6 close square brackets space equals 1 over 64 left parenthesis 6 plus 1 right parenthesis space equals space 7 over 64 space equals space 0.1094$

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Probability

An unbiased coin is tossed six times. Find the probability of obtaining more than 4 heads.

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