An unbiased coin is tossed six times. Find the probability of obtaining exactly 4 heads.

Solution

Here n = 6
p = Probability of head = $1 half comma space space straight q space equals space 1 space minus space straight p space equals space 1 minus 1 half space equals 1 half$
P (exactly 4 heads) = P (4)
$equals space straight C presuperscript 6 subscript 4 space open parentheses 1 half close parentheses squared space open parentheses 1 half close parentheses to the power of 4 space equals space straight C presuperscript 6 subscript 2 space cross times space open parentheses 1 half close parentheses to the power of 6 space equals space fraction numerator 6 space cross times space 5 over denominator 1 space cross times 2 end fraction cross times 1 over 64 space equals 15 over 64 equals space 0.2344$

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Probability

An unbiased coin is tossed six times. Find the probability of obtaining exactly 4 heads.

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