Question

The probabilities that a bulb produced by a factory will fuse after 160 days is 0·06. Find the probability that out of 5 such bulbs, at the most one bulb will fuse after 160 days of use.

Solution

Here n = 5, p = 0.06 = $6 over 100 space equals space 3 over 50 comma space space space straight q space equals space 1 space minus space straight p space equals space 1 minus 3 over 50 space equals space 47 over 50$
P(at most one bulb will fuse) = P(0) + P(1)
$equals space straight C presuperscript 5 subscript 0 open parentheses 47 over 50 close parentheses to the power of 5 space plus space straight C presuperscript 5 subscript 1 open parentheses 47 over 50 close parentheses to the power of 4 space open parentheses 3 over 50 close parentheses space equals space open parentheses 47 over 50 close parentheses to the power of 4 space open square brackets 1 space cross times space 47 over 50 plus 15 over 50 close square brackets space equals space open parentheses 47 over 50 close parentheses to the power of 4 space cross times 62 over 50 space equals space 0.9681$

For Daily Free Study Material Join wiredfaculty

Probability

The probabilities that a bulb produced by a factory will fuse after 160 days is 0·06. Find the probability that out of 5 such bulbs, at the most one bulb will fuse after 160 days of use.

Some More Questions From Probability Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

Phone Number

Email Address

Location