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Probability

Question
CBSEENMA12033828

A die is tossed twice. Getting a number greater than 4 is considered a success. Find the variance of the probability distribution of the number of successes.

Solution
The number of successes is a random variable. Let us denote it by X. X can take the values 0, 1, 2.
The number greater than 4 is 5 or 6. Let S denote the successes in getting 5 or 6.
therefore space space space straight P left parenthesis straight S right parenthesis space equals space straight P left parenthesis 5 space or space 6 right parenthesis space equals space 2 over 6 space equals space 1 third
space space space space space space space space straight P open parentheses straight S with bar on top close parentheses space equals space 1 minus 1 third space equals space 2 over 3
therefore space space space space straight P left parenthesis straight X space equals space 0 right parenthesis space equals space straight P left parenthesis straight S with bar on top space. space straight S with bar on top right parenthesis space equals space 2 over 3 cross times 2 over 3 space equals space 4 over 9
space space space space space space space space straight P left parenthesis straight X space equals space 1 right parenthesis space equals space straight P left parenthesis straight S. space straight S with bar on top right parenthesis space plus space straight P left parenthesis straight S with bar on top space. space straight S right parenthesis space equals space 1 third cross times 2 over 3 plus 2 over 3 cross times 1 third space equals 4 over 9
space space space space space space space space space straight P left parenthesis straight X space equals space 2 right parenthesis space equals space straight P left parenthesis straight S. space straight S right parenthesis space equals space 1 third cross times 1 third space equals space 1 over 9
therefore      X takes the values 0, 1, 2 with probabilities 4 over 9 comma space 4 over 9 space and space 1 over 9 respectively.

straight mu space equals space sum straight x space straight p subscript straight i space equals space 2 over 3
therefore space space space space straight sigma squared space equals space sum space straight x squared space straight p subscript straight i space minus space straight mu squared space equals space 8 over 9 minus 4 over 9 space equals 4 over 9
therefore space space space variance space equals space 4 over 9.

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