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Probability

Question
CBSEENMA12033819

Two dice are thrown simultaneously. If X denotes the number of sixes, find the expectation of X.

Solution

When a dice is rolled once, probability of obtaining six = 1 over 6
and probability of obtaining a non-six = 5 over 6
Now X can take values 0, 1, 2.
P(X = 0) = P(six does not appear a die) = P(non-six on both dice)
                          equals space 5 over 6 cross times 5 over 6 space equals space 25 over 36
P(X = 1) = P(six appear exactly on one die)
                = P(six on first die and non-six on the second die)
                                                   + P(six on the second die and non-six on the first die)
              equals space 1 over 6 cross times 5 over 6 plus 1 over 6 cross times 5 over 6 space equals space 5 over 36 plus 5 over 36 space equals 10 over 36
P(X = 2) = P(six on both the dice) = 1 over 6 cross times 1 over 6 space equals 1 over 36
∴    probability distribution of X is

∴            Expectation of X = mean of the variable X
equals space sum from blank to blank of XP left parenthesis straight X right parenthesis space equals space 0 space cross times 25 over 36 plus 1 cross times 10 over 36 plus 2 cross times 1 over 36
equals space 0 plus 10 over 36 plus 2 over 36 space equals 12 over 36 space equals 1 third.

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