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Probability

Question
CBSEENMA12033818

Find the mean μ, variance σ2 for the following probability distribution:


Solution

(i) Mean            straight mu space equals space sum from blank to blank of straight X thin space straight P left parenthesis straight X right parenthesis space equals space 36 over 30 space equals space 1.2

(ii) Variance       straight sigma squared space equals space sum from blank to blank of straight X squared straight P left parenthesis straight X right parenthesis space minus space left square bracket sum from blank to blank of straight X thin space straight P left parenthesis straight X right parenthesis right square bracket squared
                               equals space 60 over 30 minus left parenthesis 1.2 right parenthesis squared space space equals space 2 minus 1.44 space equals space 0.56.
                   

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