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Probability

Question
CBSEENMA12033817

Find the mean μ, variance σ2 for the following probability distribution:


Solution

Mean  straight mu space equals space sum from blank to blank of XP left parenthesis straight X right parenthesis

              equals space 12 over 8 space equals space 3 over 2 space equals space 1.5
Variance   straight sigma squared space equals space sum from blank to blank of straight X squared space straight P left parenthesis straight X right parenthesis space space minus space left parenthesis sum from blank to blank of straight X thin space straight P left parenthesis straight X right parenthesis right parenthesis squared space space
                       equals space 24 over 8 space minus space left parenthesis 1.5 right parenthesis squared
space equals 3 minus 2.25 space equals space 0.75

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