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Probability

Question
CBSEENMA12033797

Find the probability distribution of X, the number of heads, in the two tosses of a coin (or a simultaneous toss of two coins).

Solution
Here X can take the values 0, 1 or 2.
straight P left parenthesis straight X space equals space 0 right parenthesis space equals space straight P left parenthesis no space heads right parenthesis
                  = P(tails on first loss and tails on the second toss)
                  = P(tails on first toss) x P(tails on second toss)
                  equals space 1 half cross times 1 half space equals 1 fourth
P(X = 1) = P(1 head) = P(HT or TH)
               = P(HT) + P(TH)
                equals space 1 fourth plus 1 fourth space equals space 1 half
P(X = 2) = P(2 heads) = P(HH) = 1 fourth


                 

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