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Probability

Question
CBSEENMA12033795

A coin is tossed 4 times. X is the number of heads observed. Find the probability distribution of X.

Solution

Here X denotes the number of heads obtained in three tosses of a coin. X can take the values 0, 1, 2, 3, 4.
Let p be the probability of getting a head and q be the probability of not getting a head.
therefore space space space straight p space equals space 1 half comma space space straight q space equals space 1 space minus space straight p space equals space 1 space minus space 1 half space equals 1 half
straight P left parenthesis straight X space equals space 0 right parenthesis space equals space straight q space cross times space straight q space cross times space straight q space cross times space straight q space space equals space 1 half cross times 1 half cross times 1 half cross times 1 half space equals 1 over 16
straight P left parenthesis straight X space equals space 1 right parenthesis space equals space straight p space straight q space straight q space straight q space space plus space straight q space straight p space straight q space straight q space plus space straight q space straight q space straight p space straight q space plus space straight q space straight q space straight q space straight p
space space space space space space space space space space space space space space space space space space equals space 1 half cross times 1 half space cross times 1 half cross times 1 half plus 1 half cross times 1 half space cross times 1 half cross times 1 half plus 1 half cross times 1 half space cross times 1 half cross times 1 half plus 1 half cross times 1 half space cross times 1 half cross times 1 half
space space space space space space space space space space space space space space space space space space equals space 1 over 16 plus 1 over 16 plus 1 over 16 plus 1 over 16 space equals 4 over 16
P(X = 2) = p p q q  + p q p q  + q p p q + p q q p + q p q p + q q p p
                
equals space 1 half cross times 1 half cross times 1 half cross times 1 half plus 1 half cross times 1 half cross times 1 half cross times 1 half plus 1 half cross times 1 half cross times 1 half cross times 1 half plus 1 half cross times 1 half cross times 1 half cross times 1 half
                                                       plus 1 half cross times 1 half cross times 1 half cross times 1 half plus 1 half cross times 1 half cross times 1 half cross times 1 half space equals 6 over 16
P(X  = 3) = p p p q + p p q p + p q p p + q p p p 
               equals space 1 half cross times 1 half cross times 1 half cross times 1 half plus 1 half cross times 1 half cross times 1 half cross times 1 half plus 1 half cross times 1 half cross times 1 half cross times 1 half plus 1 half cross times 1 half cross times 1 half cross times 1 half
equals space 1 over 16 plus 1 over 16 plus 1 over 16 plus 1 over 16 space equals 4 over 16
P(X = 4) =  p p p p = 1 half cross times 1 half cross times 1 half cross times 1 half space equals space 1 over 16
 ∴ probability distribution of X is

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