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Probability

Question
CBSEENMA12033779

Coloured balls are distributed in four boxes as shown in the following table:

Box

 

Colour

 
 

Black

White

Red

Blue

I

3

4

5

6

II

2

2

2

2

III

1

2

3

1

IV

4

3

1

5

 

A box is selected at random and then a ball is randomly drawn from the selected box. The colour of the ball is black, what is the probability that ball drawn is from the box III?

Solution

Let A, E1, E2, E3 and E4 be the events as defined below:
A : a black ball is selected    E1 : box I is selected
E: box II is selected    E: box II is selected
E4 : box IV is selected
Since the boxes are chosen at random.
therefore space space space space straight P left parenthesis straight E subscript 1 right parenthesis space equals space straight P left parenthesis straight E subscript 2 right parenthesis space equals straight P left parenthesis straight E subscript 3 right parenthesis space equals space straight P left parenthesis straight E subscript 4 right parenthesis space equals space 1 fourth
Also,  straight P left parenthesis straight A vertical line straight E subscript 1 right parenthesis space equals space 3 over 18 comma space space straight P left parenthesis straight A vertical line straight E subscript 2 right parenthesis space equals space 2 over 8 comma space space straight P left parenthesis straight A vertical line straight E subscript 3 right parenthesis space equals space 1 over 7 comma space space straight P left parenthesis straight A vertical line straight E subscript 4 right parenthesis space equals space 4 over 13
P(box III is selected, given that the drawn ball is black) = P(E3 | A).
          equals space fraction numerator straight P left parenthesis straight E subscript 3 right parenthesis. space straight P left parenthesis straight A vertical line straight E subscript 3 right parenthesis over denominator straight P left parenthesis straight E subscript 1 right parenthesis thin space straight P left parenthesis straight A thin space vertical line straight E subscript 1 right parenthesis space plus space straight P left parenthesis straight E subscript 2 right parenthesis thin space straight P left parenthesis straight A vertical line straight E subscript 2 right parenthesis space plus space straight P left parenthesis straight E subscript 3 right parenthesis thin space straight P left parenthesis straight A vertical line straight E subscript 3 right parenthesis space plus space straight P left parenthesis straight E subscript 4 right parenthesis thin space straight P left parenthesis straight A vertical line straight E subscript 4 right parenthesis end fraction
                                                                                                 open square brackets because space of space Baye apostrophe straight s space Theorem right square bracket close square brackets
equals space fraction numerator begin display style 1 fourth end style cross times begin display style 1 over 7 end style over denominator begin display style 1 fourth end style cross times begin display style 3 over 18 end style plus begin display style 1 fourth end style cross times begin display style 1 fourth end style cross times begin display style 1 over 7 end style plus begin display style 1 fourth end style cross times begin display style 4 over 13 end style end fraction space equals fraction numerator begin display style 1 over 7 end style over denominator begin display style 1 over 6 end style plus begin display style 1 fourth end style plus begin display style 1 over 7 end style plus begin display style 4 over 13 end style end fraction
equals space fraction numerator 0.14 over denominator 0.17 plus 0.25 plus 0.14 plus 0.30 end fraction
equals space fraction numerator 0.14 over denominator 0.86 end fraction space equals 0.16
                  

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