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Probability

Question
CBSEENMA12033777

Let there be three urns containing 1 white, 2 black, 3 red balls ; 2 white, 1 black, 1 red ball ; 4 white, 5 black, 3 red balls. One urn is chosen at random and two balls are drawn. These happen to be white and a red. What is the probability that they come from urn number 3.

Solution
Let E1 , E2, E3 be events of selecting urns I, II, III respectively.
                             White  Black   Red
Urn I:                       1       2         3
Urn II:                      2       1         1
Urn III:                     4       5         3  

Let A be the event that the drawn balls are, one red and one white.
Since, the urns are equally likely
straight P left parenthesis straight E subscript 1 right parenthesis space equals space 1 third comma space space straight P left parenthesis straight E subscript 2 right parenthesis space equals space 1 third comma space space straight P left parenthesis straight E subscript 3 right parenthesis space equals space 1 third
∴    P( A/E1) = Probability that one red and one white ball are drawn from first urn
                       equals fraction numerator space straight C presuperscript 1 subscript 1 cross times straight C presuperscript 3 subscript 1 over denominator straight C presuperscript 6 subscript 2 end fraction space equals space 3 over 15 space equals space 1 fifth
straight P left parenthesis straight A divided by straight E subscript 2 right parenthesis space equals space fraction numerator straight C presuperscript 1 subscript 1 cross times straight C presuperscript 2 subscript 1 over denominator straight C presuperscript 4 subscript 2 end fraction space equals 1 third comma space space space space straight P left parenthesis straight A divided by straight E subscript 3 right parenthesis space equals space fraction numerator straight C presuperscript 3 subscript 1 cross times straight C presuperscript 4 subscript 1 over denominator straight C presuperscript 12 subscript 2 end fraction equals space 2 over 11
straight P left parenthesis straight E subscript 3 divided by straight A right parenthesis space equals space fraction numerator straight P left parenthesis straight E subscript 3 right parenthesis. space space space straight P left parenthesis straight A divided by straight E subscript 3 right parenthesis over denominator straight P left parenthesis straight E subscript 1 right parenthesis. space straight P left parenthesis straight A divided by straight E subscript 1 right parenthesis space plus space straight P left parenthesis straight E subscript 2 right parenthesis. space straight P left parenthesis straight A divided by straight E subscript 2 right parenthesis space plus space straight P left parenthesis straight E subscript 3 right parenthesis. space straight P left parenthesis straight A divided by straight E subscript 3 right parenthesis end fraction
space space space space space space space space space space space space space space space space space equals space fraction numerator begin display style 1 third end style cross times begin display style 2 over 11 end style over denominator begin display style 1 third end style cross times begin display style 1 fifth end style plus begin display style 1 third end style cross times begin display style 1 third end style plus begin display style 1 third end style cross times begin display style 2 over 11 end style end fraction space equals fraction numerator begin display style 2 over 11 end style over denominator begin display style 1 fifth end style plus begin display style 1 third end style plus begin display style 2 over 11 end style end fraction space equals fraction numerator begin display style 2 over 11 end style over denominator begin display style fraction numerator 33 plus 55 plus 30 over denominator 165 end fraction end style end fraction
                   equals space 2 over 11 cross times 165 over 118 space equals 15 over 59

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