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Probability

Question
CBSEENMA12033771

A manufacturer has three machine operators A, B and C. The first operator A produces 1% defective items, where as the other two operators B and C produce 5% and 7% defective items respectively. A is on the job for 50% of the time, B is on the job for 30% of the time and C is on the job for 20% of the time. A defective item is produced, what is the probability that it was produced by A?

Solution

Let E1, E2, E3, E be the events
E1 : ‘Item is produced by operator A’,
E: ‘Item is produced by operator B’,
E3 : ‘Item is produced by operator C’,
E : ‘Item chosen is found defective’
                 therefore space space space straight P left parenthesis straight E subscript 1 right parenthesis space equals space 50 over 100 comma space space straight P left parenthesis straight E subscript 2 right parenthesis space equals space 30 over 100 space space and space space straight P left parenthesis straight E subscript 3 right parenthesis space equals space 20 over 100.
           straight P left parenthesis straight E space vertical line space straight E subscript 1 right parenthesis space equals space 1 over 100 comma space space space space straight P left parenthesis straight E space vertical line space straight E subscript 2 right parenthesis space equals space 5 over 100 comma space space space straight P left parenthesis straight E space vertical line thin space straight E subscript 3 right parenthesis space equals space 7 over 100.
Required probability  = straight P left parenthesis straight E subscript 1 space vertical line thin space straight E right parenthesis
                         equals space fraction numerator straight P left parenthesis straight E subscript 1 right parenthesis thin space straight P left parenthesis straight E space vertical line thin space straight E subscript 1 right parenthesis over denominator straight P left parenthesis straight E subscript 1 right parenthesis thin space straight P left parenthesis straight E space vertical line space straight E subscript 1 right parenthesis space plus space straight P left parenthesis straight E subscript 2 right parenthesis thin space straight P left parenthesis straight E space vertical line space straight E subscript 2 right parenthesis space plus space straight P left parenthesis straight E subscript 3 right parenthesis thin space straight P left parenthesis straight E space vertical line space straight E subscript 3 right parenthesis end fraction
                                                                                  (By Baye's Theorem)
                      equals space fraction numerator begin display style 50 over 100 end style cross times begin display style 1 over 100 end style over denominator begin display style 50 over 100 end style cross times begin display style 1 over 100 end style plus begin display style 30 over 100 end style cross times begin display style 5 over 100 end style plus begin display style 20 over 100 end style cross times begin display style 7 over 100 end style end fraction space equals fraction numerator 50 over denominator 50 plus 150 plus 140 end fraction space equals 50 over 340 space equals 5 over 34.

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