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Probability

Question
CBSEENMA12033757

If a machine is correctly set up, it produces 90% acceptable items. If it is incorrectly set up, it produces only 40% acceptable items. Past experience shows that 80% of the set ups are correctly done. If after a certain set up, the machine produces 2 acceptable items, find the probability that the machine is correctly setup.

Solution

Let A be the event that the machine produces 2 acceptable items.
Again, let B1 represent the event of correct setup and B2 represent the event of incorrect setup.
        Now,     straight P left parenthesis straight B subscript 1 right parenthesis space equals space 0.8 comma space space space straight P left parenthesis straight B subscript 2 right parenthesis space equals space 0.2
                      straight P left parenthesis straight A space vertical line space straight B subscript 1 right parenthesis space equals space 0.9 space cross times space 0.9 space space and space straight P left parenthesis straight A space vertical line space straight B subscript 2 right parenthesis space equals space 0.4 space cross times space 0.4
 therefore space space straight P left parenthesis straight B subscript 1 space vertical line space straight A right parenthesis space equals space fraction numerator straight P left parenthesis straight B subscript 1 right parenthesis thin space straight P left parenthesis straight A space vertical line thin space straight B subscript 1 right parenthesis over denominator straight P left parenthesis straight B subscript 1 right parenthesis thin space straight P left parenthesis straight A space vertical line thin space straight B subscript 1 right parenthesis space plus space straight P left parenthesis straight B subscript 2 right parenthesis space straight P left parenthesis straight A space vertical line thin space straight B subscript 2 right parenthesis end fraction
space space space space space space space space space space space space space space space space equals space fraction numerator 0.8 space cross times 0.9 space cross times 0.9 over denominator 0.8 cross times 0.9 cross times 0.9 plus 0.2 cross times 0.4 cross times 0.4 end fraction equals space fraction numerator 648 over denominator 648 plus 32 end fraction space equals space 648 over 680 equals space 0.95 

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