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Probability

Question
CBSEENMA12033754

In answering a question on a multiple choice test, a student either knows the answer or guesses. Let 3 over 4 be the probability that he knows the answer and 1 fourth be the probability that he guesses. Assuming that a student who guesses at the answer will be correct with probability 1 fourth. What is the probability  that the student knows the answer given that he answered it correctly?

Solution

Let E1, E2, E be the events
E1 : ‘the student knows the answer’
E2 : ‘the student guesses the answer’,
E : ‘the answer is correct’
      therefore space space space space straight P left parenthesis straight E subscript 1 right parenthesis space equals space 3 over 4 space space and space straight P left parenthesis straight E subscript 2 right parenthesis space equals space 1 fourth
         straight P left parenthesis straight E space vertical line space straight E subscript 1 right parenthesis space equals space 1 space space space and space straight P left parenthesis straight E space vertical line space straight E subscript 2 right parenthesis space equals 1 fourth
                                                open square brackets because space space when space the space student space knows space the space answer comma space it space is space straight a space sure space event close square brackets
Required space probability space equals space straight P left parenthesis straight E subscript 1 vertical line straight E right parenthesis space equals space fraction numerator straight P left parenthesis straight E subscript 1 right parenthesis thin space straight P left parenthesis straight E vertical line straight E subscript 1 right parenthesis over denominator straight P left parenthesis straight E subscript 1 right parenthesis thin space straight P left parenthesis straight E space vertical line space straight E subscript 1 right parenthesis space plus space straight P left parenthesis straight E subscript 2 right parenthesis thin space straight P left parenthesis straight E space vertical line space straight E subscript 2 right parenthesis end fraction
                                                                                              (By Baye's Theorem)
                                    equals space fraction numerator begin display style 3 over 4 end style cross times 1 over denominator begin display style 3 over 4 end style cross times 1 plus begin display style 1 fourth end style cross times begin display style 1 fourth end style end fraction equals space fraction numerator begin display style 3 over 4 end style over denominator begin display style 3 over 4 end style plus begin display style 1 over 16 end style end fraction equals fraction numerator begin display style 3 over 4 end style over denominator begin display style fraction numerator 12 plus 1 over denominator 16 end fraction end style end fraction
equals space 3 over 4 cross times 16 over 13 space equals 12 over 13.
                                  
                

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