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Probability

Question
CBSEENMA12033710

Surjit and Sachdev appeared for an interview. The probability of their selection is 1 third space and space 1 over 6 respectively. Find the probability only one of them selected.

Solution

Let A : Surjit is selected
B ; Sachdev is selected
therefore space space space straight P left parenthesis straight A right parenthesis space equals space 1 third comma space space straight P left parenthesis straight B right parenthesis space equals space 1 over 6
 P(only one is selected) = P('A and not B' or 'B and not A')
                                      = P(A and not B) + P(B and not A)
                                      = P(A) P(not B) + P(B) P(not A)
                                      = P(A) [1 - P(B)] + P(B) [1 - P(A)]
                                        equals space 1 third open parentheses 1 minus 1 over 6 close parentheses plus space 1 over 6 open parentheses 1 minus 1 third close parentheses
equals space 1 third cross times 5 over 6 plus 1 over 6 cross times 2 over 3 space equals 5 over 18 plus 2 over 18 equals space 7 over 18.
                                        


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