Question
A bag contains 3 red and 5 black balls and second bag contains 6 red and 4 black balls. A ball is drawn from each bag. Find the probability that one is red and other is black.
Solution
In first bag, there are 3 red and 5 black ball. In second bag, there are 6 red and 4 black balls.
P (one red and one black ball)= P (‘one red from first bag and one black from second bag’ or ‘one black from first bag and one red from second bag’)
= P (one red from first bag and one black from second bag) + P (one black from first bag and one red from second bag).
