Question

A bag contains 5 white and 3 black balls. Four balls are drawn one at a time without replacement. Find the probability that the ball are alternatively of different colours.

Solution

Number of white balls = 5
Number of black balls = 3
∴ total number of balls = 5 + 3 = 8
P (balls are of alternatively of different colours)
$space equals straight P left parenthesis apostrophe WBWB apostrophe space space or space space space apostrophe BWBW apostrophe right parenthesis space space equals space straight P thin space left parenthesis WBWB right parenthesis space plus space straight P left parenthesis BWBW right parenthesis space equals 3 over 8 cross times 5 over 7 cross times 2 over 6 cross times 4 over 5 plus 3 over 8 cross times 5 over 7 cross times 2 over 6 cross times 4 over 5 space equals 1 over 14 plus 1 over 14 space equals space 1 over 7$

For Daily Free Study Material Join wiredfaculty

Probability

A bag contains 5 white and 3 black balls. Four balls are drawn one at a time without replacement. Find the probability that the ball are alternatively of different colours.

Some More Questions From Probability Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

Phone Number

Email Address

Location