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Probability

Question
CBSEENMA12033631

Let E and F be events with straight P left parenthesis straight E right parenthesis space equals space 3 over 5 comma space straight P left parenthesis straight F right parenthesis space equals space 3 over 10 space and space straight P left parenthesis straight E space intersection space straight F right parenthesis space equals space 1 fifth. Are E and F independent?

Solution

 straight P left parenthesis straight E right parenthesis space equals 3 over 5 comma space space space straight P left parenthesis straight F right parenthesis space equals 3 over 10 comma space space straight P left parenthesis straight E intersection straight F right parenthesis space equals 1 fifth
 Now comma space straight P left parenthesis straight E right parenthesis. space straight P left parenthesis straight F right parenthesis space equals space 3 over 5 cross times 3 over 10 space equals 9 over 50 not equal to space straight P left parenthesis straight E intersection straight F right parenthesis space space space space space space space space space space open square brackets because space space space straight P left parenthesis straight E intersection straight F right parenthesis space equals space 1 fifth close square brackets
therefore space space space space space space space space straight P left parenthesis straight E right parenthesis. space straight P left parenthesis straight F right parenthesis space space space not equal to space straight P left parenthesis straight E intersection straight F right parenthesis


∴ E and F are not independent.

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