If $straight P left parenthesis straight A right parenthesis space equals space 3 over 5 space and space straight P left parenthesis straight B right parenthesis space equals space 1 fifth comma$ find P(A ∩ B) if A and B are independent events.

Solution

Here, $straight P left parenthesis straight A right parenthesis space equals 3 over 5 comma space space straight P left parenthesis straight B right parenthesis space equals space 1 fifth$ ...(1)
Since A and B are independent events
$therefore space space space space space space space space space space space straight P left parenthesis straight A intersection straight B right parenthesis space equals straight P left parenthesis straight A right parenthesis space straight P left parenthesis straight B right parenthesis space equals space 3 over 5 cross times 1 fifth space space space space space space space space space space space space space space space space space space space space left square bracket because space of space left parenthesis 1 right parenthesis space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 3 over 25$

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Probability

If $straight P left parenthesis straight A right parenthesis space equals space 3 over 5 space and space straight P left parenthesis straight B right parenthesis space equals space 1 fifth comma$ find P(A ∩ B) if A and B are independent events.

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