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Probability

Question
CBSEENMA12033606
Wired Faculty App

A coin is tossed three times, where
E : at least two heads , F : at most two heads

Solution

Here S = {HHH, HHT, HTH, THH, TTH, THT, HTT, TTT}
            E : at least two heads
therefore space space space space straight E space equals space left curly bracket HHH comma space HHT comma space HTH comma space THH right curly bracket
        F: at most two heads
therefore space space space space straight F space equals space left curly bracket HHT comma space HTH comma space THH comma space TTH comma space THT comma space HTT comma space TTT right curly bracket therefore space space straight E space intersection thin space straight F space equals space left curly bracket HHT comma space HTH comma space THH right curly bracket therefore space space space straight P left parenthesis straight E right parenthesis space equals space 4 over 8 space equals space 1 half comma space space straight P left parenthesis straight F right parenthesis space equals space 7 over 8 comma space space space straight P left parenthesis straight E intersection straight F right parenthesis space equals space 3 over 8 therefore space space space straight P left parenthesis straight E space space left enclose straight F right parenthesis space equals space fraction numerator straight P left parenthesis straight E intersection straight F right parenthesis over denominator straight P left parenthesis straight F right parenthesis end fraction space equals space fraction numerator begin display style 3 over 8 end style over denominator begin display style 7 over 8 end style end fraction space equals space 3 over 7

                  

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