Question
An urn contains 6 red and 4 blue balls. Two balls are drawn at random with replacement. Find the probability of getting one red and one blue ball.
Solution
Number of red balls = 6
Number of blue balls = 4
Total number of balls = 6 + 4 = 10
P(one of them is red and other blue) = P(RB) + P(BR) = P(R) + P(B) + P(B) P(R)
