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Probability

Question

An urn contains 7 red and 4 blue balls. Two balls are drawn at random with replacement. Find the probability of getting one red and one blue ball.

Solution

Number of red balls = 7
Number of blue balls = 4
$therefore space space space space total space number space of space balls space equals space 7 plus 4 space equals space 11$
P (one red and one blue ball) = $7 over 11 cross times 4 over 11 plus 4 over 11 cross times 7 over 11 space equals 56 over 121$

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Probability

An urn contains 7 red and 4 blue balls. Two balls are drawn at random with replacement. Find the probability of getting one red and one blue ball.

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