Two balls are drawn at random with replacement from a box containing 10 black and 8 red balls. Find the probability that first ball is black and second is red.

Solution

Number of black balls = 10
Number of red balls = 8
Total number of balls = 10 + 8 = 18
P(first ball is black and second is red) = P(BR)
$equals space straight P left parenthesis straight B right parenthesis space straight P left parenthesis straight R right parenthesis space equals space 10 over 8 cross times 8 over 18 space equals 20 over 81$

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Probability

Two balls are drawn at random with replacement from a box containing 10 black and 8 red balls. Find the probability that first ball is black and second is red.

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