An urn contains 25 balls numbered 1 to 25. Two balls are drawn from the urn with replacement. Find the probability of getting at least one odd number .

Solution

Total number of balls = 25
∴ Total number of cases = 25
Let E denote the event of drawing even numbered ball and O denote the event of drawing odd numbered ball.
Number of balls numbered odd = 13
Number of balls numbered even = 12
$therefore space space space space space space space space space straight P left parenthesis straight E right parenthesis space equals space 12 over 25 comma space space straight P left parenthesis straight O right parenthesis space equals space 13 over 25$
Probaility of getting both the balls even numbered
= P(EE) = P(E) P(E) = $12 over 25 cross times 12 over 25 space equals space 144 over 625$
P(at least one odd) = 1 - P(EE) = 1 - $144 over 625 space equals 481 over 625$

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Probability

An urn contains 25 balls numbered 1 to 25. Two balls are drawn from the urn with replacement. Find the probability of getting at least one odd number .

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