Question

An urn contains 25 balls numbered 1 to 25. Two balls are drawn from the urn with replacement. Find the probability of getting one odd and one even number.

Solution

Total number of balls = 25
∴ Total number of cases = 25
Let E denote the event of drawing even numbered ball and O denote the event of drawing odd numbered ball.
Number of balls numbered odd = 13
Number of balls numbered even = 12
$therefore space space space space space space space space space straight P left parenthesis straight E right parenthesis space equals space 12 over 25 comma space space straight P left parenthesis straight O right parenthesis space equals space 13 over 25$
$therefore space space straight P left parenthesis one space odd space and space one space even right parenthesis space equals space straight P left parenthesis OE space or space EO right parenthesis space equals space straight P left parenthesis straight O right parenthesis space straight P left parenthesis straight E right parenthesis space plus space straight P left parenthesis straight E right parenthesis space straight P left parenthesis straight O right parenthesis space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 13 over 25 cross times 12 over 25 plus 12 over 25 cross times 13 over 25 space equals 312 over 625$

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Probability

An urn contains 25 balls numbered 1 to 25. Two balls are drawn from the urn with replacement. Find the probability of getting one odd and one even number.

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