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Probability

Question
CBSEENMA12033650

Given two independent events A and B such that P(A) = 0.3, P(B) = 0.6. Find P(A or B).

Solution

Here P(A) = 0.3,    P(B) = 0.6
therefore space space space space space space space space space space straight P space open parentheses straight A with bar on top close parentheses equals space 1 minus straight P left parenthesis straight A right parenthesis space equals space 1 minus 0.3 space equals 0.7
space space space space space space space space space space space space space straight P open parentheses straight B with bar on top close parentheses space equals space 1 minus space straight P left parenthesis straight B right parenthesis space equals space 1 minus 0.6 space equals space 0.4    
 P(A or B) = P(A)+P(B) - straight P left parenthesis straight A intersection straight B right parenthesis  = 0.3 + 0.6 - 0.18  = 0.72

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