Given two independent events A and B such that P(A) = 0.3, P(B) = 0.6. Find P(A and not B).

Solution

Here P(A) = 0.3, P(B) = 0.6
$therefore space space space space space space space space space space straight P space open parentheses straight A with bar on top close parentheses equals space 1 minus straight P left parenthesis straight A right parenthesis space equals space 1 minus 0.3 space equals 0.7 space space space space space space space space space space space space space straight P open parentheses straight B with bar on top close parentheses space equals space 1 minus space straight P left parenthesis straight B right parenthesis space equals space 1 minus 0.6 space equals space 0.4$
P(A and not B) = $straight P left parenthesis straight A right parenthesis space cross times space straight P space left parenthesis straight B with bar on top right parenthesis space equals 0.3 space cross times space 0.4 space equals space 0.12$

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Probability

Given two independent events A and B such that P(A) = 0.3, P(B) = 0.6. Find P(A and not B).

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