Question
Show that the line lies in the plane
Solution
The equation of given plane is

or
...(1)
The equation of given line is
...(2)
Now line (2) passes through the point (2, -3, 5), With position vector
and is parallel to the vector 
Now plane (1) passes through the point with position vector
if
i.e. if (2) (-3) + (-3) (-1) + (5) (1) = 2
i.e. if 2 = 2, which is true
Now,
is a vector normal to the plane (1). It will be perpendicular to the line (2) if it is perpendicular
i.e. if (–3) (1) + (– 1) (– 1) + (1) (2) = 0
i.e. if –3 + 1+ 2 = 0
i.e. if 0 = 0, which is true
∴ line (2) lies in plane (1).

or

The equation of given line is

Now line (2) passes through the point (2, -3, 5), With position vector


Now plane (1) passes through the point with position vector

if

i.e. if (2) (-3) + (-3) (-1) + (5) (1) = 2
i.e. if 2 = 2, which is true
Now,


i.e. if (–3) (1) + (– 1) (– 1) + (1) (2) = 0
i.e. if –3 + 1+ 2 = 0
i.e. if 0 = 0, which is true
∴ line (2) lies in plane (1).