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Three Dimensional Geometry

Question
CBSEENMA12033509

Show that the lines fraction numerator straight x minus 1 over denominator 3 end fraction space equals space fraction numerator straight y plus 1 over denominator 2 end fraction space equals fraction numerator straight z minus 1 over denominator 5 end fraction space space and space fraction numerator straight x minus 2 over denominator 4 end fraction space equals space fraction numerator straight y minus 1 over denominator 3 end fraction space equals space fraction numerator straight z plus 1 over denominator negative 2 end fraction do not intersect each other. 

Solution
The equations of lines are
         fraction numerator straight x minus 1 over denominator 3 end fraction space equals space fraction numerator straight y plus 1 over denominator 2 end fraction space equals space fraction numerator straight z minus 1 over denominator 5 end fraction                       ...(1)
      fraction numerator straight x minus 2 over denominator 4 end fraction space equals space fraction numerator straight y minus 1 over denominator 3 end fraction space equals space fraction numerator straight z plus 1 over denominator negative 2 end fraction                           ...(2)
Any point on the line (1) is (3r + 1, 2r – 1, 5r + 1)
It lies on line (2)
  if  fraction numerator 3 straight r plus 1 minus 2 over denominator 4 end fraction space equals space fraction numerator 2 straight r minus 1 minus 1 over denominator 3 end fraction space equals space fraction numerator 5 straight r plus 1 plus 1 over denominator negative 2 end fraction
i.e., if fraction numerator 3 straight r minus 1 over denominator 4 end fraction space equals space fraction numerator 2 straight r minus 2 over denominator 3 end fraction space equals space fraction numerator 5 straight r plus 2 over denominator negative 2 end fraction                ...(3)
From the first and second numbers,
              fraction numerator 3 straight r minus 1 over denominator 4 end fraction space equals space fraction numerator 2 straight r minus 2 over denominator 3 end fraction space space space space space space space or space space space space 9 straight r minus 3 space equals space 8
or space space space straight r space equals space minus 5
Substituting this value of r in (3), we get,
fraction numerator negative 15 minus 1 over denominator 4 end fraction space equals space fraction numerator negative 10 minus 2 over denominator 3 end fraction space equals fraction numerator negative 25 plus 2 over denominator negative 2 end fraction
or     negative 4 space equals space minus 4 space space equals 23 over 2 comma which is not true
∴    the given lines do not intersect.