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Three Dimensional Geometry

Question
CBSEENMA12033505

Find the vector and Cartesian form of the equation of the plane passing through the point (1, 2, –4) and parallel to the lines
             straight r with rightwards arrow on top space equals straight i with hat on top space plus space 2 space straight j with hat on top space minus space 4 space straight k with hat on top space plus space straight lambda open parentheses 2 straight i with hat on top space plus space 3 space straight j with hat on top space plus space 6 space straight k with hat on top close parentheses
and       straight r with rightwards arrow on top space equals space straight i with hat on top space minus space 3 space straight j with hat on top space plus space space 5 space straight k with hat on top space plus space straight mu space open parentheses straight i with hat on top space plus space straight j with hat on top space minus space straight k with hat on top close parentheses

Solution

Here,         straight a with rightwards arrow on top space equals space straight i with hat on top space plus space 2 space straight j with hat on top space minus space 4 straight k with hat on top comma space space space straight b with rightwards arrow on top space equals space 2 straight i with hat on top space plus space 3 space straight j with hat on top space plus space 6 space straight k with hat on top comma space space straight c with rightwards arrow on top space equals space straight i with hat on top space plus space straight j with hat on top space minus space straight k with hat on top
The vector equation of plane is
                             open parentheses straight r with rightwards arrow on top minus straight a with rightwards arrow on top close parentheses. space open parentheses straight b with rightwards arrow on top space cross times space straight c with rightwards arrow on top close parentheses space equals 0
or space space space space open square brackets straight r with rightwards arrow on top space minus space left parenthesis straight i with hat on top space plus space 2 space straight j with hat on top space minus space 4 space straight k with hat on top right parenthesis close square brackets space. space open square brackets left parenthesis 2 space straight i with hat on top space plus space 3 space straight j with hat on top space plus space 6 space straight k with hat on top right parenthesis space cross times space left parenthesis straight i with hat on top space plus space straight j with hat on top space minus space straight k with hat on top right parenthesis close square brackets space equals space 0
Cartesian equation of plane is
           open vertical bar table row cell straight x minus 1 end cell cell straight y minus 2 end cell cell straight z plus 4 end cell row 2 3 6 row 1 1 cell negative 1 end cell end table close vertical bar space equals space 0
or   left parenthesis straight x minus 1 right parenthesis space open vertical bar table row 3 6 row 1 cell negative 1 end cell end table close vertical bar space minus space left parenthesis straight y minus 2 right parenthesis space open vertical bar table row 2 6 row 1 cell negative 1 end cell end table close vertical bar space plus space left parenthesis straight z plus 4 right parenthesis space open vertical bar table row 2 3 row 1 1 end table close vertical bar space equals space 0

or    (–3 – 6) (x – 1) – (–2 – 6) (y – 2) + (2 – 3) (z + 4) = 0
or    –9 (x– 1) + 8 (y – 2) – (z + 4) = 0
or    –9x + 9 + 8y –16-z – 4 = 0
or    –9 x + 8 y – z – 11 = 0 or 9 x – 8 y + z + 11 = 0.

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