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Probability

Question
CBSEENMA12033589

A fair die is rolled. Consider events E = {1, 3, 5}, F = {2, 3} and G = {2, 3, 4, 5}. Find  P(E|F) and P(F|E).

Solution

Since fair die is rolled
therefore space space space straight S space equals space open curly brackets 1 comma space 2 comma space 3 comma space 4 comma space 5 comma space 6 close curly brackets.
        straight E space equals open curly brackets 1 comma space 3 comma space 5 close curly brackets comma space space space straight F space equals space open curly brackets 2 comma space 3 comma close curly brackets comma space space straight G space equals space open curly brackets 2 comma space 3 comma space 4 comma space 5 close curly brackets
          straight E space intersection space straight F space equals space open curly brackets 3 close curly brackets
therefore space space space space space straight P left parenthesis straight E right parenthesis space equals space 3 over 6 comma space space space straight P left parenthesis straight F right parenthesis space equals space 2 over 6 comma space space straight P left parenthesis straight E intersection straight F right parenthesis space equals space 1 over 6
therefore space space space straight P left parenthesis straight E space left enclose straight F right parenthesis space equals fraction numerator straight P left parenthesis straight E intersection straight F right parenthesis over denominator straight P left parenthesis straight F right parenthesis end fraction space equals fraction numerator begin display style 1 over 6 end style over denominator begin display style 2 over 6 end style end fraction space equals 1 half
  straight P left parenthesis straight F space left enclose straight E right parenthesis space equals space fraction numerator straight P left parenthesis straight F intersection straight E right parenthesis over denominator straight P left parenthesis straight F right parenthesis end fraction space equals fraction numerator begin display style 1 over 6 end style over denominator begin display style 3 over 6 end style end fraction space equals 1 third

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