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Three Dimensional Geometry

Question
CBSEENMA12033435

Find the equations of the planes that passes through three points:
(1, 1, 0),  (1, 2, 1), (–2, 2, –1)

Solution

The given points are (1,1, 0), (1, 2,1), (–2, 2, –1).
These points are not collinear.
The equation of plane passing through these points is
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or  open vertical bar table row cell straight x minus 1 end cell cell straight y minus 1 end cell straight z row 0 1 1 row cell negative 3 end cell 1 cell negative 1 end cell end table close vertical bar space equals space 0
   or space space open parentheses straight x minus 1 close parentheses space space open vertical bar table row 1 1 row 1 cell negative 1 end cell end table close vertical bar space minus space left parenthesis straight y minus 1 right parenthesis space open vertical bar table row 0 1 row cell negative 3 end cell cell negative 1 end cell end table close vertical bar space plus space straight z space open vertical bar table row 0 1 row cell negative 3 end cell 1 end table close vertical bar space equals space 0
or space space left parenthesis straight x minus 1 right parenthesis thin space left parenthesis negative 1 minus 1 right parenthesis space minus space left parenthesis straight y minus 1 right parenthesis space left parenthesis 0 plus 3 right parenthesis space plus space straight z space left parenthesis 0 plus 3 right parenthesis space equals space 0
or space space minus 2 straight x plus 2 minus 3 straight y plus 3 plus space 3 straight z space equals space 0 space space space space space or space space space 2 straight x plus 3 straight y minus 3 straight z space equals space 5

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