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Three Dimensional Geometry

Question
CBSEENMA12033411

In the following cases, determine whether the given planes are parallel or perpendicular, and in case they are neither, find the angles between them:
2x – y + 3z – 1 = 0 and 2x – y + 3z + 3 = 0

Solution

The given planes are
2x – + 3z – 1 = 0    ...(1)
and 2x – y + 3z + 3 = 0    ...(2)
Direction ratios of normal to plane (1) are 2, –1, 3.
Direction ratios of normal to plane (2) are 2, – 1, 3.
Now, 2 over 2 space equals space fraction numerator negative 1 over denominator negative 1 end fraction equals 3 over 3
∴ given planes (1) and (2) are parallel.

Some More Questions From Three Dimensional Geometry Chapter

Find the direction cosines of x, y and z-axis.