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Three Dimensional Geometry

Question
CBSEENMA12033410

In the following cases, determine whether the given planes are parallel or perpendicular, and in case they are neither, find the angles between them:
2x – 2y + 4z + 5 = 0 and 3x – 3y + 6z – 1 = 0

Solution

The given planes are
2x – 2 y + 4 z + 5 = 0    ...(1)
and 3 x – 3 y + 6 z –  1 = 0    ...(2)
Direction ratios of normal to plane (1) are 2, –2, 4,
Direction ratios of normal to plane (2) are 3, – 3, 6.
Now, 2 over 3 space equals space fraction numerator negative 2 over denominator negative 3 end fraction space equals space 4 over 6
∴ given planes (1) and (2) are parallel.

Some More Questions From Three Dimensional Geometry Chapter

Find the direction cosines of x, y and z-axis.