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Three Dimensional Geometry

Question
CBSEENMA12033402

Find the vector equation of the line passing through the point (3, 1, 2) and perpendicular to the plane straight r with rightwards arrow on top. space open parentheses 2 straight i with hat on top space minus space straight j with hat on top space plus space straight k with hat on top close parentheses space equals space 4. Find also the point of intersection of this line and plane. 

Solution
The equation of plane is straight r with rightwards arrow on top. space open parentheses 2 space straight i with hat on top space minus space straight j with hat on top space plus space straight k with hat on top close parentheses space equals space 4                      ....(1)
Vector along the normal to the plane is 2 straight i with hat on top minus straight j with hat on top plus straight k with hat on top
Now required line passes through point (3, 1, 2) with position vector 3 space straight i with hat on top space plus space straight j with hat on top space plus space 2 space straight k with hat on top and is parallel to the vector 2 space straight i with hat on top space minus space straight j with hat on top space plus space straight k with hat on top.
                                straight r with rightwards arrow on top space equals space open parentheses 3 space straight i with hat on top space plus space straight j with hat on top space plus space 2 space straight k with hat on top close parentheses space plus straight lambda space open parentheses 2 space straight i with hat on top space minus space straight j with hat on top space plus space straight k with hat on top close parentheses              ...(2)
        ∴ equation of line is                                                         open square brackets because space straight r with rightwards arrow on top space equals straight a with rightwards arrow on top space plus straight lambda straight m with rightwards arrow on top close square brackets
Now line (2) meets plane (1) when
        open curly brackets 3 space straight i with hat on top space plus space straight j with hat on top space plus space 2 space straight k with hat on top space plus space straight lambda space left parenthesis 2 straight i with hat on top space minus space straight j with hat on top space plus space straight k with hat on top right parenthesis close curly brackets space. space left parenthesis 2 space straight i with hat on top space minus space straight j with hat on top space plus space straight k with hat on top right parenthesis space equals space 4
straight i. straight e. space space space when space open curly brackets left parenthesis 3 plus 2 straight lambda right parenthesis straight i with hat on top space plus space left parenthesis 1 minus straight lambda right parenthesis space straight j with hat on top space plus space left parenthesis 2 plus straight lambda right parenthesis space straight k with hat on top close curly brackets. space open parentheses 2 space straight i with hat on top space minus space straight j with hat on top space plus space straight k with hat on top close parentheses space equals space 4
straight i. straight e. space when space space 2 space left parenthesis 3 plus 2 space straight lambda right parenthesis space plus space left parenthesis negative 1 right parenthesis thin space left parenthesis 1 minus straight lambda right parenthesis space plus space left parenthesis 1 right parenthesis thin space left parenthesis 2 plus straight lambda right parenthesis space equals space 4
straight i. straight e. space when space 6 plus 4 straight lambda minus 1 plus straight lambda plus 2 plus straight lambda space equals space 4
straight i. straight e. space when space 6 straight lambda space equals space minus 3 space comma space space space space space straight i. straight e. comma space when space space straight lambda space space equals space minus 1 half
Putting this value of λ in (2), we get the position vector of the point of intersection of (1) and (2) as
                    straight r with rightwards arrow on top space equals space open parentheses 3 space straight i with hat on top space plus space straight j with hat on top space plus space 2 space straight k with hat on top close parentheses space minus space 1 half left parenthesis 2 space straight i with hat on top space minus space straight j with hat on top space plus space straight k with hat on top right parenthesis space equals space 2 space straight i with hat on top space plus space 3 over 2 straight j with hat on top space plus 3 over 2 straight k with hat on top
therefore space space space required space point space is space open parentheses 2 comma space 3 over 2 comma space 3 over 2 close parentheses.

Some More Questions From Three Dimensional Geometry Chapter

Find the direction cosines of x, y and z-axis.