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Three Dimensional Geometry

Question
CBSEENMA12033491

Find the distance of the point (- 2, 3, - 4) from the line fraction numerator straight x plus 2 over denominator 3 end fraction space equals space fraction numerator 2 straight y plus 3 over denominator 4 end fraction space equals space fraction numerator 3 straight z plus 4 over denominator 5 end fraction measured  parallel to the plane 4 x + 12 y - 3z + 1 = 0.

Solution
The equations of given line are
                  fraction numerator straight x plus 2 over denominator 3 end fraction space equals space fraction numerator 2 straight y plus 3 over denominator 4 end fraction space equals space fraction numerator 3 straight z plus 4 over denominator 5 end fraction
or              fraction numerator straight x plus 2 over denominator 3 end fraction space equals space fraction numerator straight y plus begin display style 3 over 2 end style over denominator 2 end fraction space equals space fraction numerator straight z plus begin display style 4 over 3 end style over denominator begin display style 5 over 3 end style end fraction space equals space straight r space left parenthesis say right parenthesis
Any point Q on this line is open parentheses 3 straight r minus 2 comma space space 2 straight r minus 3 over 2 comma space 5 over 3 straight r space minus space 4 over 3 close parentheses
Let given point be P(– 2, 3, – 4). Direction ratios of PQ are
3 straight r minus 2 plus 2 comma space space space 2 straight r minus 3 over 2 minus 3 comma space space 5 over 3 straight r minus 4 over 3 plus 4 space space straight i. straight e. space 3 straight r comma space space 2 straight r minus 9 over 2 comma space space fraction numerator 5 straight r over denominator 3 end fraction plus 8 over 3
Since PQ is parallel to the plane
                         4 straight x plus 12 straight y minus 3 straight z plus 1 space equals space 0
therefore space 4 space left parenthesis 3 straight r right parenthesis space plus space 12 space open parentheses 2 straight r minus space 9 over 2 close parentheses space plus space left parenthesis negative 3 right parenthesis space open parentheses fraction numerator 5 straight r over denominator 3 end fraction plus 8 over 3 close parentheses space equals space 0
therefore space space space 12 straight r space plus space 24 straight r space minus space 54 space minus space 5 straight r space minus space 8 space equals space 0
space therefore space space space space space space space space space 31 space straight r space equals space 62 space space space space rightwards double arrow space space space space straight r space equals space 2
therefore space space space space space space space space space space space straight Q space is space open parentheses 6 minus 2 comma space space 4 minus 3 over 2 comma space space 10 over 3 minus 4 over 3 close parentheses space straight i. straight e. comma space space space space space open parentheses 4 comma space 5 over 2 comma space 2 close parentheses
∴   required length = PQ
equals space square root of left parenthesis 4 plus 2 right parenthesis squared plus open parentheses 5 over 2 minus 3 close parentheses squared plus left parenthesis 2 plus 4 right parenthesis squared end root
equals space square root of 36 plus 1 fourth plus 36 end root space equals space square root of fraction numerator 144 plus 1 plus 144 over denominator 4 end fraction end root space equals space square root of 289 over 4 end root space equals space 17 over 2 space units. space

Some More Questions From Three Dimensional Geometry Chapter

Find the direction cosines of x, y and z-axis.