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Three Dimensional Geometry

Question
CBSEENMA12033485

If a variable plane at a constant distance p from the origin meets the coordinate axes in points A, B and C respectively. Through these points, planes are drawn parallel to the coordinate planes. Then show that the locus of the point of intersection is
1 over straight x squared plus 1 over straight y squared plus 1 over straight z squared space equals space 1 over straight p squared.

Solution
Let O be the origin and OA = a, OB = b, OC = c
 ∴  the equation of the plane passing through A, B and C is
           straight x over straight a plus straight y over straight b plus straight z over straight c equals 1 space space space space space space space or space space space straight x over straight a plus straight y over straight b plus straight z over straight c minus 1 space equals space 0
From the given condition,  fraction numerator open vertical bar 0 plus 0 plus 0 minus 1 close vertical bar over denominator square root of begin display style 1 over straight a squared end style plus begin display style 1 over straight b squared end style plus begin display style 1 over straight c squared end style end root end fraction space equals space straight p
rightwards double arrow space space space space space square root of 1 over straight a squared plus 1 over straight b squared plus 1 over straight c squared end root space equals 1 over straight p space space space space space space space rightwards double arrow space space space space 1 over straight a squared plus 1 over straight b squared plus 1 over straight c squared space equals space 1 over straight p squared space space space space space space... left parenthesis 1 right parenthesis

The equation of plane through A (a, 0, 0) parallel to YZ-plane is x = a ... (2)
The equation of plane through B (0, b, 0) parallel to ZX-plane is y = b ... (3)
The equation of plane through C (0, 0, c) parallel to XY-plane is z = c ... (4)
Now to find the locus, we are to eliminate a, b, c.
Putting the values of a, b, c from (2), (3), (4) in (1), we get,
1 over straight x squared plus 1 over straight y squared plus 1 over straight z squared space equals 1 over straight p squared


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