Question
Find the angle between the line 
and the plane 3x + 4y + z + 5 = 0.
Solution
The equation of line is
Its direction ratios are 3, – 1, 2.
The equation of plane is 3.x + 4y + z + 5 = 0
∴ direction ratios of the normal to the plane are 3, 4, 1.
Let θ be the angle between the line and the plane
Its direction ratios are 3, – 1, 2.
The equation of plane is 3.x + 4y + z + 5 = 0
∴ direction ratios of the normal to the plane are 3, 4, 1.
Let θ be the angle between the line and the plane
