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Three Dimensional Geometry

Question
CBSEENMA12033466

Find the angle between the line straight r with rightwards arrow on top space equals space open parentheses 2 space straight i with hat on top space minus straight j with hat on top space plus space 3 space straight k with hat on top close parentheses space plus space straight lambda open parentheses 3 space straight i with hat on top space minus space straight j with hat on top space plus space 2 space straight k with hat on top close parentheses and the plane straight r with rightwards arrow on top. space open parentheses straight i with hat on top space plus space straight j with hat on top space plus space straight k with hat on top close parentheses space equals space 3

Solution
The equation of line is
                straight r with rightwards arrow on top space equals space open parentheses 2 space straight i with hat on top space minus space straight j with hat on top space plus space 3 space straight k with hat on top close parentheses space plus space straight lambda space left parenthesis 3 straight i with hat on top space minus space straight j with hat on top space plus space 2 space straight k with hat on top right parenthesis
therefore space space space space space straight b with rightwards arrow on top space equals space 3 space straight i with hat on top space minus space straight j with hat on top space plus space 2 space straight k with hat on top
The equation of plane is
               straight r with rightwards arrow on top. space open parentheses straight i with hat on top space plus space straight j with hat on top space plus space straight k with hat on top close parentheses space space equals 3
therefore space space space space space space straight n with rightwards arrow on top space equals space straight i with hat on top space plus space straight j with hat on top space plus space straight k with hat on top
Let θ be the angle between the line and plane
therefore space space space sin space straight theta space equals space fraction numerator straight b with rightwards arrow on top. space straight n with rightwards arrow on top over denominator open vertical bar straight b with rightwards arrow on top close vertical bar space open vertical bar straight n with rightwards arrow on top close vertical bar end fraction space equals space fraction numerator left parenthesis 3 right parenthesis thin space left parenthesis 1 right parenthesis space plus space left parenthesis negative 1 right parenthesis thin space left parenthesis 1 right parenthesis space plus space left parenthesis 2 right parenthesis thin space left parenthesis 1 right parenthesis over denominator square root of 9 plus 1 plus 4 end root space square root of 1 plus 1 plus 1 end root end fraction
therefore space space space space sin space straight theta space equals space fraction numerator 4 over denominator square root of 14 space square root of 3 end fraction space space equals space fraction numerator 4 over denominator square root of 42 end fraction space space space space space space rightwards double arrow space space space space space straight theta space equals space sin to the power of negative 1 end exponent open parentheses fraction numerator 4 over denominator square root of 42 end fraction close parentheses.