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Three Dimensional Geometry

Question
CBSEENMA12033465

Find the angle between the line straight r with rightwards arrow on top space equals space 2 space straight i with hat on top space plus 3 space straight j with hat on top space plus space 9 space straight k with hat on top space plus space straight lambda left parenthesis 2 straight i with hat on top space plus space 3 space straight j with hat on top space plus space 4 space straight k with hat on top right parenthesis and the plane straight r with rightwards arrow on top. space open parentheses straight i with hat on top space plus space straight j with hat on top space plus space straight k with hat on top close parentheses space equals space 5

Solution
The equation of line is
           straight r with rightwards arrow on top space equals space 2 straight i with hat on top space plus space 3 straight j with hat on top space plus space 9 straight k with hat on top space plus space straight lambda left parenthesis 2 straight i with hat on top space plus space 3 straight j with hat on top space plus space 4 straight k with hat on top right parenthesis
therefore space space straight b with rightwards arrow on top space equals space 2 space straight i with hat on top space plus space 3 space straight j with hat on top space plus space 4 space straight k with hat on top
The equation of plane is
                straight r with rightwards arrow on top. space open parentheses straight i with hat on top space plus space straight j with hat on top space plus space straight k with hat on top close parentheses space equals space 5
therefore space space space straight n with rightwards arrow on top space equals space straight i with hat on top space plus space straight j with hat on top space plus space straight k with hat on top
Let θ be the angle between the line and plane
therefore space space space space sin space straight theta space equals space fraction numerator straight b with rightwards arrow on top. space straight n with rightwards arrow on top over denominator open vertical bar straight b with rightwards arrow on top close vertical bar space open vertical bar straight n with rightwards arrow on top close vertical bar end fraction space equals space fraction numerator left parenthesis 2 right parenthesis thin space left parenthesis 1 right parenthesis space plus space left parenthesis 3 right parenthesis thin space left parenthesis 1 right parenthesis space plus space left parenthesis 4 right parenthesis thin space left parenthesis 1 right parenthesis over denominator square root of 4 plus 9 plus 16 end root space square root of 1 plus 1 plus 1 end root end fraction
therefore space space sin space straight theta space equals space fraction numerator 9 over denominator square root of 29 space square root of 3 end fraction space equals space fraction numerator 3 square root of 3 over denominator square root of 29 end fraction space space space space space space rightwards double arrow space space space space space straight theta space equals sin to the power of negative 1 end exponent open parentheses fraction numerator 3 square root of 3 over denominator square root of 29 end fraction close parentheses

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