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Three Dimensional Geometry

Question
CBSEENMA12033450

A variable plane passes through a fixed point (a, b, c) and meets the co– ordinate axes in A, B. C. Show that the locus of the point common to the planes through A. B, C parallel to the co-ordinate planes is straight a over straight x plus straight b over straight y plus straight c over straight z equals 1.

Solution
Let the equation of plane be straight x over straight alpha plus straight gamma over straight beta plus straight z over straight gamma space equals space 1                    ...(1)
where OA = α, OB = β, OC = γ   ∵ plane (1) passes through (a, b, c)
therefore space space space space space straight a over straight alpha plus straight b over straight beta plus straight c over straight gamma space equals 1                                                         ...(2)
The equation of plane through A (α, 0, 0) parallel to yz-plane is
x = α    ...(3)
The equation of plane through B (β, 0, 0) parallel to zx-plane is
y = β    ...(4)
The equation of plane through C ( γ, 0, 0) parallel to xy-plane is
z =γ        ...(5)
To eliminate α, β, γ, we put the values from (3). (4), (5) in (2) and get
straight a over straight x plus straight b over straight y plus straight c over straight z equals 1 which is required locus. 

Some More Questions From Three Dimensional Geometry Chapter

Find the direction cosines of x, y and z-axis.