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Three Dimensional Geometry

Question
CBSEENMA12033330

Find the shortest distance (S.D.) between the lines:
stack straight r subscript 1 with rightwards arrow on top space equals space 2 space straight i with hat on top space plus space 3 space straight j with hat on top space plus space 4 space straight k with hat on top space plus space straight lambda space left parenthesis 2 space straight i with hat on top space minus space straight j with hat on top space plus space stack straight k right parenthesis with hat on top
stack straight r subscript 2 with rightwards arrow on top space space equals space 3 space straight i with hat on top space minus space 2 space straight j with hat on top space minus space straight k with hat on top space plus space straight mu space left parenthesis 3 space straight i with hat on top space plus space 2 space straight j with hat on top space minus space 4 space straight k with hat on top right parenthesis.

Solution
The equation of two lines areequals space Projection space of space ST space on space straight n with rightwards arrow on top space equals space ST with rightwards arrow on top. straight n with rightwards arrow on top
              stack straight r subscript 1 with rightwards arrow on top space equals space 2 space straight i with hat on top space plus space 3 space straight j with hat on top space plus space 4 space straight k with hat on top space plus space straight lambda space left parenthesis 2 space straight i with hat on top space minus space straight j with hat on top space plus space straight k with hat on top right parenthesis                         ...(1)
and     stack straight r subscript 2 with rightwards arrow on top space equals space 3 space straight i with hat on top space minus space 2 space straight j with hat on top space minus space straight k with hat on top space plus space straight mu space left parenthesis 3 space straight i with hat on top space plus space 2 space straight j with hat on top space minus space 4 space straight k with hat on top right parenthesis                         ...(2)
Comparing these equations with
            stack straight r subscript 1 with rightwards arrow on top space equals space stack straight a subscript 1 with rightwards arrow on top space plus space straight lambda space stack straight b subscript 1 with rightwards arrow on top space space and space space stack straight r subscript 2 with rightwards arrow on top space equals space stack straight a subscript 2 with rightwards arrow on top space plus space straight mu space stack straight b subscript 2 with rightwards arrow on top comma space we space get comma
stack straight a subscript 1 with rightwards arrow on top space equals space 2 space straight i with hat on top space plus space 3 space space straight j with hat on top space plus space 4 space straight k with hat on top comma space space space stack straight b subscript 1 with rightwards arrow on top space equals space 2 space straight i with hat on top space minus space straight j with hat on top space plus space straight k with hat on top
stack straight a subscript 2 with rightwards arrow on top space equals space 3 space straight i with hat on top space minus space 2 space straight j with hat on top space minus space straight k with hat on top comma space space space space stack straight b subscript 2 with rightwards arrow on top space equals space 3 space straight i with hat on top space plus space 2 space straight j with hat on top space minus space 4 space straight k with hat on top

Let S be a point on line (1) with position vectors stack straight a subscript 1 with rightwards arrow on top space space and space straight T be point on line (2) with position vectors stack straight a subscript 2 with rightwards arrow on top so that
           ST with rightwards arrow on top space equals space stack straight a subscript 2 with rightwards arrow on top space minus space stack straight a subscript 1 with rightwards arrow on top space equals space straight i with hat on top space minus space 5 space straight j with hat on top space minus space 5 space straight k with hat on top
stack straight b subscript 1 with rightwards arrow on top cross times stack straight b subscript 2 with rightwards arrow on top space equals space open vertical bar table row cell straight i with hat on top end cell cell straight j with hat on top end cell cell straight k with hat on top end cell row 2 cell negative 1 end cell 1 row 3 2 cell negative 4 end cell end table close vertical bar space equals space straight i with hat on top space open vertical bar table row cell negative 1 end cell 1 row 2 cell negative 4 end cell end table close vertical bar space minus space straight j with hat on top space open vertical bar table row 2 1 row 3 cell negative 4 end cell end table close vertical bar space plus space straight k with hat on top space open vertical bar table row 2 cell negative 1 end cell row 3 2 end table close vertical bar
            equals space left parenthesis 4 minus 2 right parenthesis space straight i with hat on top space minus space left parenthesis 8 minus 3 right parenthesis space straight j with hat on top space plus space left parenthesis 4 plus 3 right parenthesis space straight k with hat on top
equals space 2 space straight i with hat on top space plus space 11 space straight j with hat on top space plus space 7 space straight k with hat on top
Let PQ with rightwards arrow on top be S.D. vector between given lines.
therefore it is parallel to stack straight b subscript 1 with rightwards arrow on top space cross times space stack straight b subscript 2 with rightwards arrow on top. If straight n with rightwards arrow on top is unit vector along PQ with rightwards arrow on top, then
                      straight n with rightwards arrow on top space equals space fraction numerator stack straight b subscript 1 with rightwards arrow on top space cross times space stack straight b subscript 2 with rightwards arrow on top over denominator open vertical bar stack straight b subscript 1 with rightwards arrow on top cross times stack straight b subscript 2 with rightwards arrow on top close vertical bar end fraction space equals space fraction numerator 1 over denominator square root of 174 end fraction left parenthesis 2 space straight i with hat on top space plus space 1 space space straight j with hat on top space plus space 7 space straight k with hat on top right parenthesis
NOW S.D. = Projection of ST on PQ with rightwards arrow on top
                 = Projection of ST on straight n with rightwards arrow on top space equals space ST with rightwards arrow on top. space straight n with rightwards arrow on top
                 equals space left parenthesis straight i with hat on top space minus space 5 space straight j with hat on top space minus space 5 space straight k with hat on top right parenthesis. space fraction numerator 1 over denominator square root of 174 end fraction left parenthesis 2 space straight i with hat on top space plus space 11 space straight j with hat on top space plus space 7 space straight k with hat on top right parenthesis
equals space fraction numerator 1 over denominator square root of 174 end fraction open square brackets left parenthesis 1 right parenthesis thin space left parenthesis 2 right parenthesis space plus space left parenthesis negative 5 right parenthesis thin space left parenthesis 11 right parenthesis space plus space left parenthesis negative 5 right parenthesis thin space left parenthesis 7 right parenthesis close square brackets
space equals space fraction numerator 88 over denominator square root of 174 end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space left parenthesis in space magnitude right parenthesis
                 

Some More Questions From Three Dimensional Geometry Chapter

Find the direction cosines of x, y and z-axis.