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Three Dimensional Geometry

Question
CBSEENMA12033329

Show that the st. lines whose direction-cosines are given by the equations u I + v m + w n = 0,f m n + g n l + h l m = 0 are
(i) perpendicular if straight f over straight u plus straight g over straight v plus straight h over straight w equals space 0
(ii) parallel if square root of straight u space straight f space end root space plus space square root of straight v space straight g end root space plus space square root of straight w space straight h end root space space equals space 0

Solution

The direction-cosines of the two lines are given by the equations
u l + v m + w n = 0    ....(1)
f m n + g n l + h l m = 0    ....(2)
From (1),  w n = -(u l +  v m),         therefore space space straight n space equals space open parentheses fraction numerator straight u space straight l space plus space space straight v space straight m over denominator straight w end fraction close parentheses
Putting this value of n in (2), we get,
negative straight f space straight m space open parentheses fraction numerator straight u space straight l space plus space straight v space straight m over denominator straight w end fraction close parentheses space minus space straight g space straight l space space open parentheses fraction numerator straight u space straight l space plus space straight v space straight m over denominator straight w end fraction close parentheses space plus space straight h space straight l space straight m space space equals space 0
∴    –f m (u l + v m)–g l(u l + v m) + h lm w = 0
∴    –u f l m  – v f m2 – u g l– v g l m + h l m w = 0
∴    – u g l– (u f + v g – h w) Im – v f m2 = 0
or     u g l+ (u f + v g –h w )l m + v f m2 = 0
or      straight u space straight g space open parentheses straight l over straight m close parentheses squared space plus space left parenthesis straight u space straight f space plus space straight v space straight g space minus space straight h space straight w right parenthesis space open parentheses straight l over straight m close parentheses squared plus space straight v space straight f space equals space 0                      ...(3)
which is a quadratic is straight l over straight m
Let straight l subscript 1 over straight m subscript 1 comma space straight l subscript 2 over straight m subscript 2 be its roots where l1 , m1 , n1 and l2, m2, n2 are the direction-cosines of the lines.
(i) The two lines will be perpendicular when
l1 l2 + m1 m2 + n1 n2  = 0    .....(4)
From (3),   straight l subscript 1 over straight m subscript 1. space straight l subscript 2 over straight m subscript 2 space equals space fraction numerator straight v space straight f over denominator straight u space straight g end fraction
therefore     fraction numerator straight l subscript 1 straight l subscript 2 over denominator straight v space straight f end fraction space equals fraction numerator straight m subscript 1 space straight m subscript 2 over denominator straight u space straight g end fraction
or    fraction numerator straight l subscript 1 space straight l subscript 2 over denominator straight f divided by straight u end fraction space equals space fraction numerator straight m subscript 1 space straight m subscript 2 over denominator straight g divided by straight v end fraction space equals fraction numerator straight n subscript 1 space straight n subscript 2 over denominator straight h divided by straight w end fraction space equals space straight k space left parenthesis say right parenthesis                        (By symmetry)
space therefore space space space space straight l subscript 1 space straight l subscript 2 space equals space fraction numerator straight k space straight f over denominator straight u end fraction comma space space straight m subscript 1 space straight m subscript 2 space equals space fraction numerator space straight k space straight g over denominator straight v end fraction comma space space straight n subscript 1 space straight n subscript 2 space equals space fraction numerator straight k space straight h over denominator straight w end fraction
Putting in (4), we see that lines are perpendicular
if  straight k straight f over straight u plus straight k straight g over straight v plus straight k straight h over straight w equals 0
i.e., if straight f over straight u plus straight g over straight v plus straight h over straight w equals 0
which is required condition. 

(ii) The lines are parallel if l= l2, m1= m2, n1 = n2
i.e.,   if straight l subscript 1 over straight l subscript 2 space equals space straight m subscript 1 over straight m subscript 2 space space space straight i. straight e. comma space space space if space straight l subscript 1 over straight m subscript 1 space equals space straight l subscript 2 over straight m subscript 2
i.e.,    if the roots of (3) are equal
i.e.,    if disc, of (3) = 0
i.e.,    if (u f + v g – h w)2 – 4 (u g) (v f) = 0
i.e.,    if (u f + v g – h w)2 = 4 u v f g
i.e.,  if straight u space straight f plus space straight v space straight g space minus space straight h space straight w space equals space plus-or-minus 2 square root of straight u space straight v space straight f space straight g end root
i.e.,  if uf space plus space straight v space straight g space plus-or-minus space 2 space square root of straight u space straight v space straight f space straight g end root space equals space straight h space straight w
i.e., if square root of uf space plus-or-minus space space square root of straight v space straight g end root space equals space plus-or-minus space space square root of straight h space straight w end root
i.e., if square root of straight u space straight f end root space plus-or-minus space square root of straight v space straight g end root space plus-or-minus space square root of straight h space straight w end root space equals space 0
i.e., if  square root of straight u space straight f end root space plus space square root of straight v space straight g end root space plus space square root of space straight w space straight h end root space equals space 0 space space space space space space space space space space space space space space left parenthesis taking space plus ve space signs space only right parenthesis