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Three Dimensional Geometry

Question
CBSEENMA12033310

Find the length and foot of the perpendicular drawn from the point (3, 4, 5) on the line 
fraction numerator straight x minus 2 over denominator 2 end fraction space equals space fraction numerator straight y minus 3 over denominator 5 end fraction space equals space fraction numerator straight z minus 1 over denominator 3 end fraction

Solution
Let the given line AB be fraction numerator straight x minus 2 over denominator 2 end fraction space equals space fraction numerator straight y minus 3 over denominator 5 end fraction space equals space fraction numerator straight z minus 1 over denominator 3 end fraction

Any point M on this line is
(2 r + 2, 5 r + 3, 3 r + 1)
Let this point M be the foot of perpendicular from P (3, 4, 5) on AB
Direction-ratios of PM are
2 r + 2 – 3, 5 r + 3 – 4, 3 r + 1 – 5
i.e. 2 r – 1, 5 r – 1, 3 – 4
Direction-ratios of AB are 2, 5, 3
Since PM ⊥ AB
therefore space space space space left parenthesis 2 straight r minus 1 right parenthesis thin space left parenthesis 2 right parenthesis space plus space left parenthesis 5 straight r minus 1 right parenthesis thin space left parenthesis 5 right parenthesis space plus space left parenthesis 3 straight r minus 4 right parenthesis thin space left parenthesis 3 right parenthesis space equals space 0
therefore space space space space 4 straight r minus 2 plus 25 straight r minus 5 plus 9 straight r minus 12 space equals space 0 space space space space space space rightwards double arrow space space 38 space straight r space space equals space 19
therefore space space space space space space space space space space space space straight r space equals space 1 half
therefore space space space space foot space of space perpendicular space straight M space is space open parentheses 1 plus 2 comma space 5 over 2 plus 3 comma space 3 over 2 plus 1 close parentheses space space space straight i. straight e. space space space space space open parentheses 3 comma space 11 over 2 comma space 5 over 2 close parentheses
Required length of perpendicular = PM
equals space square root of left parenthesis 3 minus 3 right parenthesis squared plus open parentheses 4 minus 11 over 2 close parentheses squared plus open parentheses 5 minus 5 over 2 close parentheses squared end root space equals space square root of 0 plus 9 over 4 plus 25 over 4 end root space equals space square root of 34 over 4 end root space equals space fraction numerator square root of 34 over denominator 2 end fraction.

Some More Questions From Three Dimensional Geometry Chapter

Find the direction cosines of x, y and z-axis.