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Three Dimensional Geometry

Question
CBSEENMA12033395

Find the vector equation of the following planes in scalar product form:
straight r with rightwards arrow on top space equals space 2 space straight i with hat on top space minus space straight k with hat on top space plus space straight lambda space straight i with hat on top space plus space straight mu space open parentheses straight i with hat on top space minus space 2 space space straight j with hat on top space minus space straight k with hat on top close parentheses

Solution
The equation of plane is straight r with rightwards arrow on top space equals space 2 space straight i with hat on top space minus space straight k with hat on top space plus space straight lambda space straight i with hat on top space plus space straight mu space open parentheses straight i with hat on top space minus space 2 space space straight j with hat on top space minus space straight k with hat on top close parentheses
or  straight x straight i with hat on top space plus space straight y straight j with hat on top space plus space straight z straight k with hat on top space equals space open parentheses 2 plus straight lambda plus straight mu close parentheses straight i with hat on top space minus space 2 space straight mu space straight j with hat on top space plus space left parenthesis negative 1 minus straight mu right parenthesis space straight k with hat on top
Equating the coefficients of straight i with hat on top comma space straight j with hat on top comma space straight k with hat on top comma we get,
x = 2 + λ + μ    ... (1)
y = 2 μ    ...(2)
z = – 1– μ    ...(3)
From (2), straight mu equals negative straight y over 2
Putting this value of μ in (3), we get,
straight z equals negative 1 plus straight y over 2 space space space space space space space or space space space space 2 space straight z space equals space minus 2 plus straight y space space space or space space space straight y minus 2 space straight z space equals space 2
This can be written as open parentheses straight x space straight i with hat on top space plus space straight y space straight j with hat on top space plus space straight z space straight k with hat on top close parentheses space open parentheses straight j with hat on top space minus space 2 space straight k with hat on top close parentheses space equals space 2
or     straight r with rightwards arrow on top. space open parentheses straight j with hat on top space minus space 2 space straight k with hat on top close parentheses space equals space 2
which is the required equation. 

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