Question

Find the cartesian equation of the following plane:
$straight r with rightwards arrow on top. space open parentheses 2 space straight i with hat on top space plus space 3 space straight j with hat on top space minus space 4 space straight k with hat on top close parentheses space equals space 1$

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Solution

The equations of piane is

straight r with rightwards arrow on top space open parentheses 2 straight i with hat on top space plus space 3 straight j with hat on top space minus space 4 space straight k with hat on top close parentheses space equals space 1

open parentheses straight x space straight i with hat on top space plus space straight y space straight j with hat on top space plus space straight z space straight k with hat on top close parentheses space. space open parentheses 2 space straight i with hat on top space plus space 3 space straight j with hat on top space minus space 4 space straight k with hat on top close parentheses space equals space 1 space space space space space space space open square brackets because straight r with rightwards arrow on top space equals space straight x space straight i with hat on top space plus space straight y space straight j with hat on top space plus space straight z space straight k with hat on top close square brackets

or 2x + 3y – 4z =1 which is cartesian equation of plane.

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