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Three Dimensional Geometry

Question
CBSEENMA12033239

Find the projection of the line segment joining the points (1, 2, 3), (4, 3, 1) on the line with direction ratios 3, –6, –2.

Solution
Let P (1, 2, 3), Q (4, 3, 1) be given points and AB be the line whose direction ratios are 3; – 6, 2.
Direction cosines of AB are
fraction numerator 3 over denominator square root of 9 plus 36 plus 4 end root end fraction comma space space fraction numerator negative 6 over denominator square root of 9 plus 36 plus 4 end root end fraction comma space space fraction numerator negative 2 over denominator square root of 9 plus 36 plus 4 end root end fraction space space straight i. straight e. comma space space 3 over 7 comma space minus 6 over 7 comma space minus 2 over 7
Projection of PQ on AB = (4-1) + open parentheses 3 over 7 close parentheses plus space left parenthesis 3 minus 2 right parenthesis space open parentheses negative 6 over 7 close parentheses space plus space left parenthesis 1 minus 3 right parenthesis space open parentheses negative 2 over 7 close parentheses
                                      equals space 9 over 7 minus 6 over 7 plus 4 over 7 space equals space 7 over 1 space equals space 1.