-->

Three Dimensional Geometry

Question
CBSEENMA12033286

Find the angle between the pair of lines:
         straight r with rightwards arrow on top space equals space 3 space straight i with hat on top space plus space straight j with hat on top space minus space 2 space straight k with hat on top space plus space straight lambda space left parenthesis straight i with hat on top space minus space straight j with hat on top space minus space 2 space straight k with hat on top right parenthesis
and   straight r with rightwards arrow on top space equals space 2 space straight i with hat on top space minus space straight j with hat on top space minus space 5 space straight k with hat on top space plus space straight mu space left parenthesis 3 space straight i with hat on top space minus space 5 space straight j with hat on top space minus space 4 space straight k with hat on top right parenthesis


Solution
The equations of two lines are
            straight r with rightwards arrow on top space equals space 3 space straight i with hat on top space plus space straight j with hat on top space minus space 2 space straight k with hat on top space plus space straight lambda space left parenthesis straight i with hat on top space minus space straight j with hat on top space minus space 2 space stack straight k right parenthesis with hat on top
and      straight r with rightwards arrow on top space equals space 2 space straight i with hat on top space minus space straight j with hat on top space minus space 5 space straight k with hat on top space plus space straight mu space left parenthesis 3 space straight i with hat on top space minus space 5 space straight j with hat on top space minus space 4 space straight k with hat on top right parenthesis
therefore space space space space space space space straight b with rightwards arrow on top space equals space straight i with hat on top space minus space straight j with hat on top space minus space 2 space straight k with hat on top comma space space stack straight b apostrophe with rightwards arrow on top space equals space 3 space straight i with hat on top space minus space 5 space straight j with hat on top minus space 4 space straight k with hat on top
Let θ be angle between the lines.
therefore space space space space space space cos space straight theta space equals space fraction numerator straight b with rightwards arrow on top. space stack straight b apostrophe with rightwards arrow on top over denominator open vertical bar straight b with rightwards arrow on top close vertical bar space open vertical bar straight b with rightwards arrow on top apostrophe close vertical bar end fraction
space space space space space space space space space space space space space space space space space space space space space equals space fraction numerator left parenthesis 1 right parenthesis thin space left parenthesis 3 right parenthesis space plus space left parenthesis negative 1 right parenthesis thin space left parenthesis negative 5 right parenthesis space plus space left parenthesis negative 2 right parenthesis thin space left parenthesis negative 4 right parenthesis over denominator square root of 1 plus 1 plus 4 end root space square root of 9 plus 25 plus 16 end root end fraction space equals space fraction numerator 3 plus 5 plus 8 over denominator square root of 6 space square root of 50 end fraction
space space space space space space space space space space space space space space space space space space space space space equals space fraction numerator 16 over denominator square root of 6. space 5 square root of 2 end fraction space equals space 16 over 5 cross times fraction numerator 1 over denominator square root of 12 end fraction space equals space 16 over 5 cross times fraction numerator 1 over denominator 2 square root of 3 end fraction cross times fraction numerator square root of 3 over denominator square root of 3 end fraction space equals fraction numerator 8 square root of 3 over denominator 15 end fraction
therefore space space space space space space space space straight theta space equals space cos to the power of negative 1 end exponent open parentheses fraction numerator 8 square root of 3 over denominator 15 end fraction close parentheses.