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Three Dimensional Geometry

Question
CBSEENMA12033272

Find the vector and the cartesian equations of the line that passes through the points (3, – 2, – 5), (3, – 2, 6).

Solution
The line passes through the points A(3, 2, – 5) and B(3, –2, 6).
therefore space space space space space space space straight a with rightwards arrow on top space equals space 3 space straight i with hat on top space minus space 2 space straight j with hat on top space minus space 5 space straight k with hat on top comma space space space space straight b with rightwards arrow on top space equals space 3 space straight i with hat on top space minus space 2 space straight j with hat on top space plus space 6 space straight k with hat on top
where straight a with rightwards arrow on top comma space straight b with rightwards arrow on top are position vectors of A, B respectively.
therefore space space space space space space straight b with rightwards arrow on top minus straight a with rightwards arrow on top space space equals space 11 space straight k with hat on top
Let straight r with rightwards arrow on top be the position vector of any point on the given line. 
∴     the vector equation of line is
                        straight r with rightwards arrow on top space equals space straight a with rightwards arrow on top space plus space straight lambda space left parenthesis straight b with rightwards arrow on top minus stack straight a right parenthesis with rightwards arrow on top
or                      straight r with rightwards arrow on top space equals space 3 space straight i with hat on top space minus space 2 space straight j with hat on top space minus space 5 space straight k with hat on top space plus space 11 space straight lambda space straight k with hat on top
Taking straight r with rightwards arrow on top space equals space straight x space straight i with hat on top space plus space straight y space straight j with hat on top space plus space straight z space straight k with hat on top comma space the equation of line is
        straight x space straight i with hat on top space plus space straight y space straight j with hat on top space plus space straight z space straight k with hat on top space equals space 3 space straight i with hat on top space minus space 2 space straight j with hat on top space plus space left parenthesis negative 5 space plus space 11 space straight lambda right parenthesis space straight k with hat on top
Comparing the coefficients of straight i with hat on top comma space straight j with hat on top comma space straight k with hat on top comma space space we space get comma
                        straight x space equals space 3 comma space space space straight y space equals space minus 2 comma space space space straight z space equals space minus 5 plus 11 space straight lambda
or             fraction numerator straight x minus 3 over denominator 0 end fraction space equals space fraction numerator straight y plus 2 over denominator 0 end fraction space equals fraction numerator straight z plus 5 over denominator 11 end fraction space left parenthesis equals straight lambda right parenthesis
which is cartesian equation of line.

Some More Questions From Three Dimensional Geometry Chapter

Find the direction cosines of x, y and z-axis.